Hey diameter of a bowling ball is about 22 cm in diameter of a tennis ball is about 7 cm what is the approximate difference in volume between bowling ball and tennis ball

Step-by-step explanation:

The bowling ball and the tennis ball are spherical in shape.

The formula for determining the volume of a sphere is expressed as

Volume = 4/3 × πr³

Where

r represents the radius of the sphere.

π is a constant whose value is 3.14

Considering the bowling ball,

Diameter = 22 cm

Radius = diameter/2 = 22/2 = 11 cm

Volume = 4/3 × 3.14 × 11³ = 5572.5cm³

Considering the Tennis ball,

Diameter = 7 cm

Radius = diameter/2 = 7/2 = 3.5 cm

Volume = 4/3 × 3.14 × 3.5³ = 179.5 cm³

the approximate difference in volume between bowling ball and tennis ball is

5572.5 - 179.5 = 5393 cm³

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

y=x+9

?

step-by-step explanation: