Find the area of the surface generated when the given curve is revolved about the given axis. yequals6xplus7, for 0 less than or equals x less than or equals 2; about the x-axis

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry

i don't know, but that looks pretty bad. my school passed us unless we failed in all the subjects, but idk abt ur school's rules.

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