Christopher runs a farm stand that sells apples and bananas. Yesterday Christopher sold 35 pounds of apples and 34 pounds of bananas for a total revenue of $163.50. Today he sold 15 pounds of apples and 17 pounds of bananas for a total revenue of $76.75. Determine the price of each pound of apples and the price of each pound of bananas.

Pound of Apples = 2$

Pound of Banana = 2.75$

Step-by-step explanation:

Data

Yesterday Christopher sold 35 pounds of apples (35A) and 34 pounds of bananas (34B) for a total revenue of $163.5 (=163.50)

Today he sold 15 pounds of apples (15A) and 17 pounds of bananas (17B) for a total revenue of $76.75. (=76.75)

Now well, we have a system of the equation

35A+34B=163.50

15A+17B=76.75

we must eliminate A or B,  As you can see 34 is twice 17, so we multiply on both sides of the equation so as not to alter it

35A+34B=163.50                35A+34B=163.50                            

15A+17B=76.75 (-2) ⇒        -30A-34B=-153.50

                                              5A-0B = 10

5A=10 ⇒ A=10/5 ⇒ A=2

and B:

35(2)+34B=163.5 ⇒ 70+34B=163.5 ⇒ 34B=163.5-70

34B=93.5 = 93.5/34

B=2.75

the barter

a) 0

step-by-step explanation:

i^413 x i^0 = 0 as any number multiplied by a zero is

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