The equation for line u can be written as y = 1/9x + 9. Line v, which is parallel to line u,
includes the point (1, -1). What is the equation of line v?

The equation of line v is y = 1/9x - 10/9

Step-by-step explanation:

Given that line v is parallel to line u so it that's mean they have the same gradient/slope which is 1/9. You can use this to find equation:

y = 1/9x + c

Then, you can substitute the x value and y value from the coordinates:

At (1,-1),

-1 = 1/9(1) + c

c = -10/9

y = 1/9x - 10/9

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse