Solve the system of equations. y = x + 3 y = x2 − 2x − 1 A. (1,4) and (-4,-1) B. (-1,7) and (4,2) C. (-1,4) and (4,-1) D. (-1,2) and (4,7)

D

Step-by-step explanation:

Given the 2 equations

y = x + 3 → (1)

y = x² - 2x - 1 → (2)

Substitute y = x² - 2x - 1 into (1)

x² - 2x - 1 = x + 3 ← subtract x + 3 from both sides

x² - 3x - 4 = 0 ← in standard form

(x - 4)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 4 = 0 ⇒ x = 4

x + 1 = 0 ⇒ x = - 1

Substitute these values into (1) for corresponding values of y

x = 4 ⇒ y = 4 + 3 = 7 ⇒ (4, 7 )

x = - 1 ⇒ y = - 1 + 3 = 2 ⇒ (- 1, 2 )

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation:

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!