At a school carnival, the diameter of the mat of a trampoline is 12 feet and the diameter of its metal frame is 14 feet. What is the length, in feet, of the metal frame that surrounds the trampoline? Use 3.14 for π and round your answer to the nearest tenth.

The length, of the metal frame that surrounds the trampoline is 44.0 feet.

Step-by-step explanation:

Given:

At a school carnival, the diameter of the mat of a trampoline is 12 feet and the diameter of its metal frame is 14 feet.

Use 3.14 for π.

Now, to find the length, in feet, of the metal frame that surrounds the trampoline.

As given, diameter is 14 feet.

So, radius (r) =

Now, to get the length of the metal frame we put formula of circumference:

So, rounding into nearest tenth = 44.0 feet.

Therefore, the length, of the metal frame that surrounds the trampoline is 44.0 feet.

44.0 feet

Step-by-step explanation:

geometry: triangles

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lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

8+10

step-by-step explanation:

you multiply 4 by 2 and 5 by 2