A deck of cards is shuffled and dealt to four players, with each receiving 13 cards. Find: a. the probability that the first player holds all the aces; b. the probability that the first player holds all the aces given that she holds the ace of hearts; c. the probability that the first player holds all the aces given that she holds at least one; d. the probability that the second player holds all the aces given that he holds all the hearts.

A.4/52

B.1/52

C.4/42

D.12/52

Step-by-step explanation:

A. Because there is 52 cards in a deck the answer will be out of 52. Since there is 4 aces in the whole deck the probability of player one getting all four aces is a 4/52.

B. Since there is 52 cards in a deck and only one ace of hearts it will be a probability of 1/52.

C. Since there are 52 cards in a deck the probability that they will hold an ace card is a 4/52 Bc there are four aces.

D. Because there are 52 cards in a deck, and 12 hearts in the deck in all they will have a chance of 12/52

You might need to simplify these fractions or convert to a percentage based on what your instructor wants.

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: