The value V of a Porsche 718 Cayman that is t years old can be modeled by
V(t) = 420,000(0.965)
t
(a) What would be worth the car′s worth in 2 years?
(b) I how may years will the car be worth $325,000?

A. V (2) = $ 391,114.50

B. t = 7.2 years (rounding to the next tenth) or approximately 7 years, 2 months and 12 days.

Step-by-step explanation:

This is the given formula:

V(t) = 420,000 * (0.965)^t

A. What would be worth the car′s worth in 2 years?

V(t) = 420,000 * (0.965)^t

We replace t by 2, as follows:

V(2) = 420,000 * (0.965)²

V(2) = 420,000 * 0.931225

V (2) = $ 391,114.50

B. In how many years will the car be worth $325,000?

V(t) = 420,000 * (0.965)^t

We replace V(t) by 325,000, as follows:

325,000 = 420,000 * (0.965)^t

325,000/420,000 = (0.965)^t

0.77381 =  (0.965)^t

t = log 0.965(0.7738)  

t = log 0.7738/log 0.965

t = 7.2 years (rounding to the next tenth) or approximately 7 years, 2 months and 12 days

0.2 years = 0.2 * 12 = 2.4 months

0.4 months = 0.4 * 30 = 12 days

f is the midpoint of

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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