Determine the discriminant for the quadratic equation 0 = –2x2 + 3. based on the discriminant value, how many real number solutions does the equation have?

discriminant = b2 – 4ac

real number solutions

Easy
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in form
0=ax^2+bx+c
discriminant is b^2-4ac

when discriminant:
1. is more than zero, you have 2 real roots
2. is equal to zero, you have 1 real root
3. is less than zero, you have 2 complex roots

in this one

0=-2x^2+0x+3
a=-2
b=0
c=3
b^2-4ac
0^2-4(-2)(3)
it is obvously greater than zero

has 2 real solutions

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