Three cards are drawn with replacement from a standard deck. What is the probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen? Express your answer as a fraction or a decimal number rounded to four decimal places.

The probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen is 0.0096

Step-by-step explanation:

Total no. of cards = 52

No. of diamond cards = 13

No. of black cards = 26

No. of queens = 4

Three cards are drawn with replacement from a standard deck.

We are supposed to find he probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen

Probability of getting diamond card =

Probability of getting black card =

Probability of queen =

Probability  that the first card will be a diamond, the second card will be a black card, and the third card will be a queen =

Hence the probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen is 0.0096

d) the triangle is a right triangle 60 squared +144 squared= 156 squared

step-by-step explanation:

156 squared is the hypothenuse

so 156= c

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation: