How many games will the cost to bowl be the same at both bowling centers if ran in lanes charges $2.50 per game plus $2 for shoe rental, and fun time lanes charges $2 per game plus $4 for shoe rental

After 4 games cost to bowl will be the same at both bowling centers.

Step-by-step explanation:

Given:

ran in lanes charges

Per game charge = $2.5

rental charge for shoe = $2

Let the number of games played be 'x'.

So we can say that;

Total cost is equal to sum of Per game charge multiplied by number of games and rental charge for shoe.

framing in equation form we get;

Total cost =

fun time lanes

Per game charge = $2

rental charge for shoe = $4

So we can say that;

Total cost is equal to sum of Per game charge multiplied by number of games and rental charge for shoe.

framing in equation form we get;

Total cost =

To find the number of games when both cost would be same we have to make the total cost of both the bowling centers to be equal.

Hence we can say that;

=

Combining the like terms we get;

Dividing both side by 0.5 we get;

Hence After 4 games cost to bowl will be the same at both bowling centers.

where are the choices?

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18