Yori is trying to prove that if segment AB is a perpendicular bisector of segment PQ, then any point, X, on segment AB is equidistant from endpoints P and Q. What is the best plan for her proof?

The angles between the vertices y'P0 and y'Q0 must be equal

α=β

Step-by-step explanation:

To demonstrate that each point of segment AB is equidistant from the end points P and Q, it is enough to take any point of segment AB and determine the angle formed between this point and points P and Q

According to the graph the angles generated by the vertices y'P0 and y'Q0 must be equal, and these are determined by the sine, cosine or tangent, we will take for example the tangent

tgα=y'/P = 5/-6 ⇒ α=atg(5/-6) ≅ -39,80° ∧ tgβ=(5/6) ⇒ β=atg(5/6) ≅ 39,80°

The negative sign indicates that the tangent is negative in that quadrant (2nd) , finally α=β

lol, i have been using this product for a while and the second half of the year for a lon and the first time in a long time ago that the government has not yet received enough votes to be a good the first place in the world to be able to do it in my world life, i

1/8 is left? add a bit more info plz