On a coordinate plane, triangle A B C has points (negative 9, 3), (negative 9, 6), (0, 3) and triangle A double-prime B double-prime C double-prime has points (3, negative 1), (3, negative 2), and (0, negative 1). Which transformations could be performed to show that △ABC is similar to △A"B"C"? a reflection over the x-axis, then a dilation by a scale factor of 3 a reflection over the x-axis, then a dilation by a scale factor of One-third a 180° rotation about the origin, then a dilation by a scale factor of 3 a 180° rotation about the origin, then a dilation by a scale factor of One-third

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

d 600 because 15*10*2=300

300+300=600

step-by-step explanation:

step-by-step explanation:

im not sure what the answer is

the median is   36 orr sum like dat

step-by-step explanation: