Two cyclist leave towns 78 miles apart at the same time and travel toward each other. One cyclist travels 5 mi/h faster than the other. If they meet in 2 hours, what is the rate of each cyclist ?

One cyclist travels at 17 m/h and the other at 22 m/h.

Step-by-step explanation:

Let one cyclist travel at x m/h and the other at (x+5) m/h.

Their combined speed is x + x + 5 = 2x+5 m/h.

When they meet the total distance they have travelled will be 78 miles.

Speed = distance / time taken, so:

2x+5 = 78/2

2x + 5 = 39

2x = 34

x = 17 m/h = speed of one cyclist.

So the other travels at 17+5 = 22 m/h.

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )

if you are looking for the unit rate then the answer would be 9 because unit rate is distance divided by time.

step-by-step explanation: