Find k if the lines 3x-5y=9 & 2x+ky=11 are a)parallel and b)perpendicular

a)

b)

Step-by-step explanation:

If two lines and ( where, and are their slope respectively ) are,

Parallel, if,

Perpendicular, if,

Here, the lines are,

3x - 5y = 9 ⇒ 5y = 3x - 9 ⇒

2x + ky = 11 ⇒ ky = -2x + 11 ⇒

a) If they are parallel,

b) If they are perpendicular,

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?