A jar contains 6 red marbles numbered 1 to 6 and 12 blue marbles numbered 1 to 12. A marble is drawn at random from the jar. Find the probability of the given event, please show your answers as reduced fractions. (a) The marble is red. P(red)= Preview (b) The marble is odd-numbered. P(odd)= Preview (c) The marble is red or odd-numbered. P(red or odd) = Preview (d) The marble is blue or even-numbered. P(blue or even) = Preview Get help: Video

(a)P(Red)=

(b)P(odd)=

(c)P(red or odd)=

(d) P(blue or even)=

Step-by-step explanation:

The contents of the jar are:

6 red marbles numbered 1 to 6.

12 blue marbles numbered 1 to 12.

Total=6+12=18

(a)Probability that the marble is Red

P(Red)=

(b)The marble is odd-numbered.

Number of Odd Numbered Red Marbles(1,3,5)=3

Number of Odd Numbered Blue Marbles(1,3,5,7,9,11)=6

Total Odd Numbered Marbles=3+6=9.

P(odd)=

(c)The marble is red or odd-numbered.

Number of Red Marbles=6

Number of Odd Numbered Marbles=9

Number of Red Odd Numbered Marbles=3

The two events are not mutually exclusive, therefore:

P(red or odd)=P(Red)+P(Odd)-P(Red and Odd)

=

(d) The marble is blue or even-numbered.

Number of Blue Marbles=12

Number of Even Numbered Marbles=6+3=9

Number of Blue Even Numbered Marbles=6

The two events are not mutually exclusive, therefore:

P(blue or even)=P(blue)+P(even)-P(blue and even)

=

the answer is 0.071

good luck! : d

step-by-step explanation:

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about the problem:

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