The area of a circle of radius r is given by A=\pi r^2A=πr 2 and its circumference is given by C=2\pi rC=2πr. At a certain point in time, the radius of the circle is r=8r=8 inches and the area of the circle is changing at a rate of \frac{dY}{dt}=\pi\sqrt{2} dt dA =π 2 square inches per second. How fast is the radius of the circle changing at this time

Step-by-step explanation:

If I'm understanding this correctly, your problem is as follows:

The area of a circle is given by the formula

The area of the circle is changing at a rate of .  Find the rate of change of the radius, , when r = 8.

Assuming that is what you are asking, we will begin by finding the derivative of the area of a circle using implicit differentiation.

Filling in what we have:

which simplifies a bit to

Divide both sides by 16π to get:

The π's cancel leaving the rate of change of the radius as

inches per second

the reporter's right

step-by-step explanation:

1/4 = .25 / 25%

i believe the correct answer is option 4.principalities were small territories that were run by russian rulers.

which statement correctly defines principalities in northern asia in the 1200s? principalities were small territories that were run by russian rulers.

hope i could ! : )