What is the center of the circle with the equation (x-1)2 + (y+3)2= 9?
a:(1,3)
b:(-1,3)
c:(-1,-3)
d:(1,-3)

The answer to your question is the letter d( 1, -3)

Step-by-step explanation:

Equation

               (x - 1)² + (y + 3)² = 9

Let's compare the equation with the standard equation of the circle

                (x - h)² + (y - k)² = r²

From the standard equation we can get the center, it is represented by the letters h and k, so for this equation the center is

             h = -1  and k = +3

but we must change the signs so,

            h = 1 and k = -3   or (1, -3)

47 - 90 = 43

43 - 180 = x

x = 137