How is domain of the function f(x)=sinx restricted so that its inverse function exists?

Correct  sin x ⇒D(x) :  [- π/2, π/2] ; sin⁻¹x ⇒ CD(x) :  [- π/2, π/2]

Step-by-step explanation:

In order for the function sin x to have an inverse function sin⁻¹x due to the monotony, the domain is taken D(x) :  [- π/2, π/2] and the range of sin⁻¹x  is CD(x) :  [- π/2, π/2].

God is with you!!!

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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this was already solved by me with a different person. if you look it up in the search bar at the top of the page, you will get the answer.

step-by-step explanation: