A rectangular poster is to contain 882 square inches of print. The margins at the top and bottom of the poster are to be 2 inches, and the margins on the left and right are to be 1 inch. What should the dimensions of the poster be so that the least amount of poster is used

L  =  23 in

h  = 46  in

Step-by-step explanation:

Let call  " x "  and  " y "  dimensions of the print area of the poster then:

882 = x*y  and   y = 882/x

We also know that dimensions of the poster is:

L  =  x + 2   in  and     h  =  y + 4 in

Therefore area of the poster is:

A(p)  = ( x + 2 ) * ( y + 4 )  And area as function of x is:

A(x)  =   ( x + 2 ) * ( 882/x + 4 )

A(x)  =  882 + 4*x + 1764 /x  + 8

Taking derivatives on both sides of the equation we have:

A´(x)  =  4  - 1764/x²

A´(x)  = 0      ⇒      4  - 1764/x² = 0      ⇒ 4*x² - 1764  =  0

x²  =  1764 / 4

x²  = 441

x  = 21 in      and    y  =  882/x         y  = 42

The second derivative  A´´(x)  is > 0  ( the second term changes its sign to +) there is a minimum for the function at the point      x = 21

As x   and  y are dimensions of the printing area of the poster, dimensions of the poster  are

L  = x  +  2   =   21  + 2  =  23 in   and

h = y  +  4   =   42  + 4  =  46  in

answer: h

step-by-step explanation:

pentagon

step-by-step explanation:

the coordinates   a(5, -2), b(3,-1),c(-4,-4) d(-3,8) and e(-1,4) forms the vertices of the polygon when they are connected in order.

in order to classify that which polygon is it with the given coordinates, first count the number of vertices and then count the number of sides it can make with these vertices.

since, the given coordinates have five vertices, therefore, it will make five sides. moreover, pentagon is regular in nature therefore it will be convex.

now, a polygon with five sides is known as pentagon, therefore, the given polygon is the pentagon.