According to a study conducted in one city, 3838% of adults in the city have credit card debts of more than $2000. A simple random sample of n equals 200n=200 adults is obtained from the city. Describe the sampling distribution of ModifyingAbove p with caretp, the sample proportion of adults who have credit card debts of more than $2000. Round to three decimal places when necessary.

The sampling distribution of the sample proportion of adults who have credit card debts of more than $2000 will be normally distributed with mean = 0.38 and standard deviation of 0.034.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p, the sampling distribution will be normally distributed with mean and standard deviation

In this problem, we have that:

So

The sampling distribution of the sample proportion of adults who have credit card debts of more than $2000 will be normally distributed with mean = 0.38 and standard deviation of 0.034.

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13