Mathematics, 30.03.2020 23:40 oceanbrezze85

The circle below is centered at (4, -1) and has a radius of 3. What is its
equation?
O A. (x-4)2+ (x-1)2 = 9
O B. (x-4)2+(y-1)2 = 3
O C. (x-4)2+(x+ 1)2 = 9
O D. (x-4)2 + (x + 1)2 = 3

Answers: 1

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The circle below is centered at (4, -1) and has a radius of 3. What is its
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O A...

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More questions: Mathematics Another questions

The circle below is centered at (4, -1) and has a radius of 3. What is its equation? O A. (x-4)2+ (x-1)2 = 9 O B. (x-4)2+(y-1)2 = 3 O C. (x-4)2+(x+ 1)2 = 9 O D. (x-4)2 + (x + 1)2 = 3

Answers

Another question on Mathematics

The circle below is centered at (4, -1) and has a radius of 3. What is its
equation?
O A. (x-4)2+ (x-1)2 = 9
O B. (x-4)2+(y-1)2 = 3
O C. (x-4)2+(x+ 1)2 = 9
O D. (x-4)2 + (x + 1)2 = 3