Name all sets square root of 27 belongs to please help me quick !

Details about all sets square root of 27 is given below.

Step-by-step explanation:

1. Square Root of 27

To an accuracy of at least . 01%, the square root of 27 is 5.196.

2. 27 = 33 = 32 * 3

sqrt(27) = sqrt(32 * 3)

= 3*sqrt(3)

sqrt(3) can't be expressed as the ratio of integers and when written as a decimal it does not terminate, so it is irrational.

Thus sqrt(27) is itself irrational.

3. Simplest form of √27

27 is not a perfect square so it does it have an exact square root.

√27 is an irrational number, but it can be written in surd form:

√27=√3×3×3.

=3√3.

4. Is 27 a perfect square number? A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 27 is about 5.196. Thus, the square root of 27 is not an integer, and therefore 27 is not a square number.

5. The number 27 can be evenly divided by 1, 3, 9 and 27, with no remainder. Since 27 cannot be divided by just 1 and 27, it is a composite number.

6. 27. All terminating decimal numbers are rational.All irrational numbers are real.

7. For 27 to be an integer, 27 has to be a whole number. Furthermore, for 27 to be an integer, you should be able to write 27 without a fractional or decimal component. 27 is a whole number that can be written without a fractional component, thus 27 is an integer.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!