A sample of 4 different calculators is randomly selected without replacement from a group containing 47 that are defective and 30 that have no defects. What is the probability that all four of the calculators selected are defective

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you can not drow on this

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i believe the answer is 68cm

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i just took 34 x 2 because the space between v and y is the same as y to k.

question 1 is 8, question 2 is 9, question 3 is 24

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now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!