Tim has 3 dice, one with 4 sides, 5 sides, and 6 sides. Each dice is fair and has faces (1, 2, ... n) where n is the number of sides. Tim proceeds as follows: he rolls each die one at a time (starting with the four-sided, then five, then six). However, if Tim ever rolls more than a three he stops rolling the dice. Let X be the sum of all the dice Tim rolled.1. Compute E[X].2. Compute P(A). Where A represents the event that Tim rolled a five with one of the die.

Ikr they be playing

F(x) =2.96.(1.04)ˣ, where x is the number of monthsprice at the origin, when x = 0→ f(x) = 2.96(1.04)⁰  →f(x) = 2.96(remember any number with exponent 0 gives 1).price after 1 month (x=1)  → f(x) =2.96.(1.04)¹ = 3.0784increase of cost = (3.0784-.96)/2.96 = 0.04 or 4% increase.however you could have noticed it from the formula: f(x) =2.96.(1.04)ˣ = 2.96(1+0.04)ˣ (and the 0.04 or 4% is the increase over 1.sorry for the 2nd part, i am confused with your "table" . i have to see a proper table in order to you