The caffeine content (in mg) was examined for a random sample of 50 cups of black coffee dispensed by a new machine. The mean and the standard deviation were 110 mg and 7.1 mg respectively. Use the data to construct a 98% confidence interval for the mean caffeine content for cups dispensed by the machine. Interpret the interval!

 We are 98% confident interval for the mean caffeine content for cups dispensed by the machine between 107.66 and 112.34 mg .

Step-by-step explanation:

Given -

The sample size is large then we can use central limit theorem

n = 50 ,  

Standard deviation = 7.1

Mean = 110

1 - confidence interval = 1 - .98 = .02

= 2.33

98% confidence interval for the mean caffeine content for cups dispensed by the machine =

                     =

                      =

       First we take  + sign

    = 112.34

now  we take  - sign

= 107.66

 We are 98% confident interval for the mean caffeine content for cups dispensed by the machine between 107.66 and 112.34 .

i think is g(1)=-1.

hope that i can