Suppose f is a function that has an inverse. Below is a table indicating some values that f assigns. Examine the table and answer the questions below it.

x – 2 – 1 0 1 2 3 4 5
f(x) 2 – 2 4. -1 1 3 5 0
What are the values of a, b, c and d that make the following true?

f( – 2) = a, f^ – 1( – 2) = b, f(c) = 0, and f^ – 1(d) = 0.

There are four text boxes below. In the first text box, enter the value of a. Your answer should be an integer; do not include letters, an equals sign, or other symbols. In the second, third and fourth textboxes, enter the values of b, c and d. After entering your value, click the Save Answer button.

Response to your input section.
Enter The Value Of a Here:
Enter The Value Of b Here:
Enter The Value Of c Here:
Enter The Value Of d Here:

4+n=5

step-by-step explanation:

this is because the four is four hours and the n represents the 1 extra hour over the weekend.

b= i'm srry i don't know that one.

4+n=5 n=1 because if vernon plays 5 hours a week then 4+1=5 hours.

hope this : )

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

r and t.

both are 64 degrees.

just get this app called photo math it should be able to do those