How many different ways can 7 people sit in seats labeled A – G? *
1 point
7 ways
5040 ways
14 ways
720 ways

The seats are arranged in 5040 ways, if 7 people sit in seats labeled A, B, C, D, E, F, G.

Step-by-step explanation:

The given is,

                 7 people sit in seats labeled A, B, C, D, E, F, G.

Step: 1

               No.of people = 7

               No. of seats labeled = 7

               Formula to calculate the number of ways to arrange,

                                      ...................................(1)

               Where, n - Positive integer

Step: 2

               From given, n = 7

               Equation (1) becomes,

                                            = 7 × 6 × 5 × 4 × 3 × 2 × 1

                                            = 5040

                                            = 5040 ways

Result:

         The seats are arranged in 5040 ways, if 7 people sit in seats labeled A, B, C, D, E, F, G.    

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.