Write the equation of the line with a slope of -5 and a y-intercept of (0,3).

write the equation of the line with a slope of -1/3 and passing through the point (6, -4).

write the equation of the line passing through the points (0, -4) and (-2, 2).

write the equation of the line passing through the points (-6,1) and (-4,2).

write the equation of the line with an undefined slope, passing through the point (2, 5).

Equation of the line with slope -5 and y intercept (0,3)
y = mx + b
y = -5x + 3
equation of line with slope -1/3 and passing through the point (6, -4)
y-y1 = m(x-x1)
y-(-4) = (-1/3)(x - 6)
y+4 =(-1/3)(x-6)
3(y+4) = -1(x-6)
3y + 12 = -x + 6
x + 3y + 12 - 6 = 0
x + 3y + 6 = 0
equation of line passing through the points (0, -4) and (-2, 2)
(y - y1)/(y2 - y1) = (x-x1)/(x2-x1)
(y + 4)/(2 + 4) = (x - 0)/(-2-0)
(y+4)/6 = x/-2
-2(y+4) = 6x
-2y - 8 = 6x
6x + 2y + 8 = 0
equation of line passing through the points (-6, 1) and (-4, 2)
(y - y1)/(y2-y1) = (x-x1)/(x2-x1)
(y-1)/(2-1) = (x+6)/(-4+6)
(y-1)/1 = (x+6)/2
2(y-1) = (x+6)
2y - 2 = x + 6
x - 2y + 6 + 2
x - 2y + 8 = 0
equation of line undefined slope passing through the point (2, 5)
y - y1 = m(x-x1)
y - y1 = tanФ(x-x1)
y - 5 = (∞)(x-2)
y - 5 = (1/0)(x-2)
0(y-5) = (x-2)
0 = x - 2
x - 2 = 0

Letter c so sorry if i’m wrong ):