Determine the critical values of f(x) = ax² + bx + c.
A critical value can occur where f'(x) = 0 and also where f'(x) does not exist. Since f'(x) is a polynomial, there are no x-values where f '(x) does not exist. Therefore, the only critical values will be where f'(x) = 0.
Solve the equation f'(x) = 0 for x.

  x = -b/(2a)

Step-by-step explanation:

Using the power rule for derivatives, you can find ...

  f'(x) = 2ax +b

Solving for x when f'(x) = 0, we have ...

  2ax +b = 0

  2ax = -b

  x = -b/(2a)

The critical value is x = -b/(2a).

the answer is c. 23/3

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: