In a study of the effect of cooling rate on the hardness of welded joints, 50 welds cooled at a rate of 10oC/s had an average Rockwell (B) hardness of 91.1 and a standard deviation of 6.44, and 40 welds cooled at a rate of 30oC/s had an average hardness of 90.7 and a standard deviation of 4.18. Ten more welds will be made in order to increase the precision of the confidence interval. Which would increase the precision the most, cooling all 10 welds at the rate of 10oC/s, cooling all 10 welds at the rate of 30oC/s, or cooling 5 welds at 10oC/s and 5 at 30oC/s? Explain.

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

step-by-step explanation:

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0lz try yourself sorry for not answering