Given \qquad \overline{BA}\perp\overline{BD} BA ⊥ BD start overline, B, A, end overline, \perp, start overline, B, D, end overline \qquad m \angle CBD = 4x + 52^\circm∠CBD=4x+52 ∘ m, angle, C, B, D, equals, 4, x, plus, 52, degrees \qquad m \angle ABC = 8x - 10^\circm∠ABC=8x−10 ∘ m, angle, A, B, C, equals, 8, x, minus, 10, degrees Find m\angle CBDm∠CBDm, angle, C, B, D:

step-by-step explanation:

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the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

i think the answer is true

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