Lola is using a one-sample t-t- test for a population mean, µμ , to test the null hypothesis, H0:µ=40 mg/dLH0:μ=40 mg/dL , against the alternative hypothesis, H1:µ>40 mg/dLH1:μ>40 mg/dL . Her results are based on a simple random sample of size n=15 . The value of the one-sample t-t- statistic is t=1.457 .

If Lola requires her results to be statistically significant at significance level of a 0.10, what can she conclude and why?

a. Because the exact p-value is unknown, she cannot make a conclusion.
b. She should not reject the null hypothesis because p > 0.10.
c. She should not reject the null hypothesis because p< 0.10.
d. She should reject the null hypothesis because p< 0.10,
e. She should not reject the null hypothesis because 0.10< p < 0.05.

Lola's conclusion should be "She should reject the null hypothesis because p< 0.10". Option D is correct.

Given information:

Lola is using a one-sample t-test for a population mean, µ, to test the null hypothesis.

Sample random size is, .

The value of the one-sample t-statistic is .

The left bound will be and the value of will be 15-1=14.

Now, use the calculator to find the value of p. The found value of p will be,

So, the value of p is less than 0.1.

Therefore, Lola's conclusion should be "She should reject the null hypothesis because p< 0.10". Option D is correct.

For more details, refer to the link:

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d. She should reject the null hypothesis because p < 0.10.

Step-by-step explanation:

We have a t statistic, so let's solve for the P-value on our calculators. (tcdf on a TI-84 calculator is 2nd->VARS->6.)

tcdf(left bound, right bound, degrees of freedom)

tcdf(1.457,999,14) = .084

.084 < P-value of .10, so we reject the null hypothesis.

the red lines denote the population of the bacteria after 35 hours. that would be 2,409.24. the y-intercept is the blue line which is 800 because that is the starting point. the equation used to make the graph is 800(1.032)^h, where h is the number of hours.

step-by-step explanation: