A classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 150 feet per second from an initial height of 86 feet off the ground, then the height of the projectile, h , in feet, t seconds after it's shot is given by the equation: h = − 16 t 2 + 150 t + 86 Find the two points in time when the object is 133 feet above the ground. Round your answers to the nearest hundredth of a second (two decimal places).

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation:

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

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so then what are you asking?

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no solution

step-by-step explanation:

there is not enough information in the problem to solve.