Both classrooms have a range of 35 points, but room B has an interquartile range of 21 points while room A interquartile range is 20 points. There are slight differences in the medians as well as the third anf first quartiles.

the answer is 5/3x+7/5y+7

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

answer: you need to organize this better it does not make sense.

step-by-step explanation: ?

the answer is mp

step-by-step explanation: