Set up a table of values and then graph the line from its parametric form. x=-3t +4 y= 2t-5

y = x -

Step-by-step explanation:

Given

So we will set up a set values of t to have x

t = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

<=> x = {4, 1, -2, -5, -8, -11, -14, -17, -20, -23, -26}

So we will set up a set values of t to have y

t = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

<=.> y = {-5, -3, -1, 1, 3, 5, 7, 9, 11, 13, 15}

At the end, we have the table of values of x and y as following:

x = {4, 1, -2, -5, -8, -11, -14, -17, -20, -23, -26}

y =  {-5, -3, -1, 1, 3, 5, 7, 9, 11, 13, 15}

Let find the slope of the linear equation:

m =  

<=> m = =

and the standard form of a linear equation is:

y= mx + b

In this situation, y = x + b (1)

Because the line goes through point (4, -5), so we substitute it into (1) to find b.

<=> -5 =  *4 + b

<=> b = -

<=> y = x -

Please have a look at the attach photo.

Hope it will find you well.

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5