How many 5 digit codes are possible if the first digit cannot be 0 or 1 and digits can be repeated?

80000

Step-by-step explanation:

The first digit is the only one with any constraints: it cannot be 1 or 0. This leaves us with 8 options (2, 3, 4, 5, 6, 7, 8, 9).

The other four digits have no such conditions, so we have 10 choices for each of them (0-9, inclusive).

So!

8 * 10 * 10 * 10 * 10 = 80000 :))

answer:

what is your question that you ask

step-by-step explanation:

5050

hope this !