A supporting wire is to be attached to the top of a 43 foot antenna. If the wire must be anchored 43 feet from the base of the antenna, what length of wire is required?

The length of the wire is 60.81 feet

Step-by-step explanation:

Hi, since the antenna and the distance from the base to the point of the anchor form a right triangle (see attachment)

We can apply the Pythagorean Theorem

c2 = a2+b2

Where c is the hypotenuse of the triangle (the longest side, or the wire in this case) and a and b are the other 2 sides.

Replacing with the values given and solving for c:

c²= 43²+43²

c =√(43²+43²)

c =√(1849+1849)

c =√3689

c = 60.81 feet

the answer would be the last one (constat) she stays at the same rat every two mintues it goes up by 0.4

step-by-step explanation:

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3