9.2.33
How many gallons of 20% antifreeze should be mixed with 10 gallons of 76% antifreeze to obtain a 55% antifreeze mixture?
gallons of 20% antifreeze should be mixed with 10 gallons of 76% antifreeze to obtain a 55% antifreeze mixture,

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

5

10

15

20

25

30

35

40

45

50

55

10.4 inches

step-by-step explanation:

2x2x2.6

step-by-step explanation:

4  

25

5258y

54.

t5

5r

54

5856

542

5458

86

.8558.65

565

565

55898

786

8/95

5896

8656265

556478