⎩

⎪

⎪

⎨

⎪

⎪

⎧



a(1)=−13

a(n)=a(n−1)+4



Find the

2nd2^{\text{nd}}

2

nd

2, start superscript, start text, n, d, end text, end superscript

term in the sequence⎩

⎪

⎪

⎨

⎪

⎪

⎧



a(1)=−13

a(n)=a(n−1)+4



Find the

2nd2^{\text{nd}}

2

nd

2, start superscript, start text, n, d, end text, end superscript

term in the sequence

The second term in the sequence is -9

Step-by-step explanation:

Given the nth term of a sequence to be a(n) = a(n-1)+4 where n is the number of terms of the sequence

If a(1) = -13... (1)

The second term of the sequence is generated for n= 2:

a(2) = a(2-1)+4

a(2) = a(1)+4... (2)

Substituting equation 1 into 2

a(2) = -13+4

a(2) = -9

The second term in the sequence is -8

step-by-step explanation:   divide the numerator by the denominator to get the decimal

it would still be 193

if divide by 100 then 1.93

i am not sure

loloo

step-by-step explanation:

lololool