A bag contains 6 red balls 8 yellow ones and 4 black ones if a ball is randomly selected find the probability of it being neither black nor yellow
A 2
9
B 5
9
C 7
9
D 1
3
E 4
9

1/3

(given answers in Question are unreadable)

Step-by-step explanation:

We search for red balls (neither yellow or black). There are 6 red balls among all 18 balls. Selecting one ball, there is a chance 6/18 that we pull out a red one. 6/18 is the same as 1/3.

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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