A sample of 90 women is obtained, and their heights (in inches) and pulse rates (in beats per minute) are measured. The linear correlation coefficient is 0.284 and the equation of the regression line is ModifyingAbove y with caret equals 18.4 plus 0.930 x, where x represents height. The mean of the 90 heights is 63.4 in and the mean of the 90 pulse rates is 77.9 beats per minute. Find the best predicted pulse rate of a woman who is 66 in tall. Use a significance level of alpha equals 0.01.

the best predicted pulse rate of a woman who is 66 in tall = 79.78 beats per minute

Step-by-step explanation:

We are given that;

Regression line: y^ = 18.4 + 0.93x

Now we want to find out the best predicted pulse rate of a woman who is 66 in tall.

Thus;

If x = 66, then the predicted height is:y^ = 18.4 + 0.93(66)

y^ = 79.78 beats per minute

maximum area = xy = (16)(32) = 512 ft2

to maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.'

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15 batches are the most you can make

step-by-step explanation: