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Harper invested $3,200 in an account paying an interest rate of 7% compounded
continuously. Assuming no deposits or withdrawals are made, how much money, to
the nearest ten dollars, would be in the account after 6 years?

Harper will have approximately 4870 dollars in 6 years.

Step-by-step explanation:

Since this investment is compounded continuosly it's growth is given by the following equation:

M = C*e^(r*t)

Where M is the final value, C is the amount invested, r is the interest rate and t is the time elapsed. Applying the data from the question we have:

M = 3200*e^(0.07*6)

M = 3200*e^(0.42)

M = 4870.28

Harper will have approximately 4870 dollars in 6 years.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

8

step-by-step explanation: