So right now i'm doing prodigy and I got this question and I can't find out what it is can I have some help the question is The sum of two numbers is 11 and their difference is 3

x = 7

y = 4

Step-by-step explanation:

The sum of two numbers equaling 11 can be written as

x + y = 3

The difference of the two numbers equaling 3 can be written as

x - y = 3

Where x and y represent the unknown numbers

So now we have a system of equations

We can solve for y in the 1st equation by subtracting x on both sides

x + y = 11

y = 11 - x

We can plug the expression for y into the 2nd equation and solve for x

x - (11 - x) = 3

x - 11 + x = 3

2x - 11 = 3

2x = 14

x = 7

Now we can plug 7 for x into any of the equations and solve for y

1st equation:

7 + y = 11

y = 4

2nd equation:

7 - y = 3

-y = -4

y = 4

So, x = 7 and y = 4

Hope this helped!

the answer is 5/3x+7/5y+7

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2