Table has an area of 12 and a perimeter of 16 feet what are the dimensions of the table

The dimensions of the table are

Step-by-step explanation:

Let x be the length of table

Let y be the breadth of table

Area of table =

We are given that Table has an area of 12 sq.feet

xy=12

-----1

Perimeter of table = 2(l+b)=2(x+y)

We are given that Perimeter is 16 feet

2(x+y)=16

x+y=8

Using 1

When x = 6

y =

When x = 2

y =

Hence the dimensions of the table are

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

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