9. Problem 52 from the Rhind Papyrus. Example of a cut-off (truncated) triangle of land. Suppose it is said to thee, What is the area of a cut-off triangle of land of 20 khet in its side, 6khet in its base, 4 khet in its cut-off line? Solution: Add its base to its cut-off line; it makes 10. Take ½ of 10, that is 5, in order to get its rectangle. Multiply 20 times 5; it makes 100 [square khets]. This is its area. This cut-off (truncated) triangle of land is a right trapezoid. Use the formula for the area of a trapezoid to verify that the solution above yields the area of the land.

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

won't that be plagrisim thought?

step-by-step explanation:

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1