In a set of three lines, a pair of parallel lines is intersected by a transversal. The intersection forms eight special angles.
Two of the special angles, A and B, are corresponding angles.
For the set of parallel lines intersected by a transversal, A = 4x and B = 2(x+14).

1. Use an equation to represent the corresponding angle relationship between A and B.

2. Use the equation to find the measures of A and B.

PLEASE HELP!!! Will mark brainliest and give thanks:) 90 points

Part A: 4x = -5(x - 18)

Part B: 40° (both, A & B)

Step-by-step explanation:

We already know the fact that angles A and B are corresponding angles. By definition, this means that A and B are equal in degree measure.

A = 4x and B = -5(x - 18), so we can just set these equal to each other.

A. 4x = -5(x - 18)

Step 1: Now, we need to solve for x.

4x = -5x - 5 * (-18) = -5x + 90

9x = 90

x = 10

Step 2: Now, you have to plug this value into each expression of A and B:

A = 4x = 4 * 10 = 40 degrees

B = -5(x - 18) = -5(10 - 18) = -5 * (-8) = 40 degrees.

Therefore,  A = B = 40 degrees.

Brainliest please, i need a few more :)

m ∡A = 56

m ∡B = 56

Step-by-step explanation:

If two parallel lines are cut by a transversal, the corresponding angles are equal.

1. ∡ A ≅ ∡B or m∡A = m ∡B

2. 4x = 2(x+14) distribute

   4x = 2x + 28     -2x on both sides

  4x -2x = 2x-2x + 28

   2x = 28 divide by 2 on both sides

  x = 14

m ∡A = 4*14=56

m ∡B = 2(14+14) = 2*28 =56

you answer is a

step-by-step explanation:

7.3

step-by-step explanation: