What is the solution to the system of equations?
y=-3x - 2
5x + 2y = 15
(-40, 19)
(-19, 55)
(19,-40)
(55, -19)

x = -19

y = 55

Step-by-step explanation:

this is a simultaneous equation. It can be solved in two different ways :

    2. Elimination method

Using elimination method:

3x +y = -2         (1)

5x + 2y =15     (2)

Multiply equation one by the coefficient of x (5) in equation 2

Multiply equation 2 by the co efficient of x (-3) in equation 1

15x + 5y = -10        (3)

15x + 6y = 45       (4)

subtract equation  4 from equation  3  ( when doing this 15x -15x= 0 which means they cancel out) so we have

-y = -55

y = 55

Substitute 55 for y in equation 1 or 2

3x +y = -2         (1)

3x + 55 = -2

3x= -2-55

3x = -57

Divide both sides of the equation by 3

x = -19

y = 55

Note : i re-arranged  y= - 3x - 2 to give 3x + y = -2

I hope it helps :)

answer: 590

step-by-step explanation:

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)