Mathematics, 03.06.2020 13:22 electrofy456

PLEASE HELP A ladder is set up against a building, as shown in the picture.

How far up does the ladder reach on the building?
Round your answer to the nearest hundredth.

A:6.67 m

B: 3.75 m

C: 0.6 m

D: 15 m

Answers: 3

Show answers

Answers

Answer from: haileysolis5

6.67 m

Step-by-step explanation:

Hello!

This is a similar triangles problem. There are different ways to approach this. We could use angles, but that involves trig. An easier way is to use ratios.

First, let's look at the picture. There are two triangles, one that has a length of 1.5 m and a height of 2 m, and a larger triangle, with a length of 5 m and a height of n m. We can relate these triangles and their lengths/heights because they are similar triangles.

So, if there are 2 triangles, we can relate

$\frac{x_{1}}{y_{1}} = \frac{x_{2}}{y_{2}}$

where $x_{1}$ and $y_{1}$ are the length and height of the first triangle and $x_{2}$ and $y_{2}$ are the length and height of the second triangle.

So, let's apply it:

$\frac{1.5}{2} = \frac{5}{n}$

Okay, and solve for the unknown, n:

$.75 = \frac{5}{n}\\.75*n = 5\\n = 6.67$

So, we found n = 6.66667 or, rounded to the nearest hundreth as the instructions state, 6.67 m. Since it's one of the listed options, that indicates we're correct. However, we should also apply a "does this make sense check": does 6.67 make sense as an answer?

Well, the length for the smaller triangle are 1.5 and 2. Those values are very close to eachother. So are 5 and 6.67. So our answer does make sense! We could also check our work by substituting 6.67 for n in our original ratio and evaluate each side of the equal sign:

$\frac{1.5}{2} = \frac{5}{6.6667}\\.75 = .75$

Yep! Through this check, we can show that our answer is correct!

Answer from: Quest

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body covers no displacement as time elapses. thus the flat line with zero gradient.

Use the drop-down menus to answer each question. which line represents the movement of a cart with a

Answer from: Quest

$20.01

step-by-step explanation:

the sale price is (1.00 - 0.77)($87), or 0.23($87), or $20.01.

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