18,500 g how many grams 22 g how many grams

4.7 kg how many grams

8.3 kg how many grams

135,000mg how many grams

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Answers:

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7000 mg = 7 g

18500 g = 18.5 kg

22 g = 22000 mg

4.7 kg = 4700 g

8.3 kg = 8300 g

135000 mg = 135 g

Step-by-step explanation:

First we need to use some important conversion rates so I will write them for below

1 Milligram (mg) = 0.001 Grams (g)

1 Gram (g) = 0.001 Kilogram (Kg)

1 Gram (g) = 1000 Milligrams (mg)

1 Kilogram (Kg) = 1000 Grams (g)

Using the above conversion rates we can solve these questions

Question 1

7000 mg = ? g

Using the information at the top 1 Milligram (mg) = 0.001 Grams (g) so,

0.001 × 7000 = 7 grams

Question 2

18500 g = ? kg

Using the information at the top 1 Gram (g) = 0.001 Kilogram (Kg) so,

18500 ÷ 1000 = 18.5 kg

Question 3

22 g = ? mg

Using the information at the top 1 Gram (g) = 1000 Milligrams (mg) so,

22 × 1000 = 22000 mg

Question 4

4.7 kg = ? g

Using the information at the top 1 Kilogram (Kg) = 1000 Grams (g) so,

4.7 × 1000 = 4700 g

Question 5

8.3 kg = ? g

Using the information at the top 1 Kilogram (Kg) = 1000 Grams (g) so,

8.3 × 1000 = 8300 g

Question 6

135000 mg = ? g

Using the information at the top 1 Milligram (mg) = 0.001 Grams (g) so,

0.001 × 135000 = 135 grams

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18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²